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200.96=12.56r^2
We move all terms to the left:
200.96-(12.56r^2)=0
We get rid of parentheses
-12.56r^2+200.96=0
a = -12.56; b = 0; c = +200.96;
Δ = b2-4ac
Δ = 02-4·(-12.56)·200.96
Δ = 10096.2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10096.2304}}{2*-12.56}=\frac{0-\sqrt{10096.2304}}{-25.12} =-\frac{\sqrt{}}{-25.12} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10096.2304}}{2*-12.56}=\frac{0+\sqrt{10096.2304}}{-25.12} =\frac{\sqrt{}}{-25.12} $
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